this post was submitted on 01 Sep 2024
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Microblog Memes

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[–] Anticorp@lemmy.world 7 points 1 month ago (7 children)

It's been forever since I learned about this experiment in school. How TF did they measure the unobserved state, since measuring is an observation? Was it indirect measuring?

[–] AnarchistArtificer@slrpnk.net 6 points 1 month ago (5 children)

The film on which the interference pattern is made is, in a sense, an observer. But the observer that most people mean is what was added after the wave-like interference pattern made researchers ask "okay, but which slit did the electron go through?" and they put a detector near the slits to determine an answer to that. When they did this, the wave function collapsed and the film no longer showed an interference pattern, but two bands, which would correspond to an particle-like electron going through either one slit or the other.

[–] Anticorp@lemmy.world 3 points 1 month ago (4 children)

Could the whole thing be misconstrued, and just the proximity of the sensor be what is causing the wave collapse, not the observation?

[–] heydo@lemmy.world 3 points 1 month ago

Basically the sensor is interacting with the quantum particle by measuring where it is before the slit. This collapses the wave function of the particle, causing it to appear at one point in space. Since the particle is collapsed to a point before the slit, it travels through only one of the slits and impacts the screen. Since it is just a single point particle now, there is no wave to interfere with the particle and create multi-line wave pattern, so we just see two straight lines on the screen that match up with the slits.

The sensor performing the measurement is the observer in this case. No living creature is needed to observe the particle to make it collapse. It's simply just, quantum particles are just wave functions up until the point that they have to collapse to a particle because it has interacted with something (a screen or a sensor or anything). That is about the limit of my understanding at least

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