this post was submitted on 07 Oct 2024
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Science Memes

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top 29 comments
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[–] spankmonkey@lemmy.world 153 points 4 days ago (5 children)

As long as we ignore the parallel sides requirement, sure.

[–] kryptonianCodeMonkey@lemmy.world 90 points 4 days ago (2 children)

And that the 90 degree angles should be interior angles.

[–] ninja@lemmy.world 45 points 4 days ago (2 children)

And that polygons should only consist of straight lines.

[–] rain_worl@lemmy.world 0 points 15 hours ago
[–] bstix@feddit.dk 34 points 4 days ago

Yes sure, in Euclidean geometry, but this is clearly keyhole shaped geometry.

[–] wolfpack86@lemmy.world 12 points 4 days ago (1 children)

They're also not actually right angles, as the curvature starts departing from the angles origin. They may be approximately 90, down to many many small decimal places, but they are not 90.

[–] kryptonianCodeMonkey@lemmy.world 22 points 4 days ago* (last edited 4 days ago)

That's not accurate. If you are measuring the angle of a line intersecting with a curved surface, you measure against the tangent at the point of contact/intersection. It can be and still is exactly 90 degrees.

[–] Prunebutt@slrpnk.net 29 points 4 days ago (2 children)

Take shitposts seriously and point out their obvious errors

-Carl Friedrich Gauss, probably

[–] Eheran@lemmy.world 21 points 4 days ago (2 children)

Science memes is not r/shitposting? I would assume the person is serious when posting here.

[–] rain_worl@lemmy.world 3 points 4 days ago

gasp!!! it is c/!!!

[–] Tja@programming.dev 2 points 4 days ago

The name of that Gauss?

Ampere

[–] lugal@sopuli.xyz 17 points 4 days ago

c/gatekeeping squares

[–] hydroptic@sopuli.xyz 10 points 4 days ago

You're no fun

[–] Tolookah@discuss.tchncs.de 5 points 4 days ago

Polar coordinate square?

[–] Lemjukes@lemm.ee 30 points 4 days ago (1 children)

I remember enough from geometry to know this is horseshit and be annoyed at it but not enough to actually prove why

[–] Tja@programming.dev 10 points 4 days ago (1 children)

Sides must be straight and parallel two and two.

[–] Doll_Tow_Jet-ski@fedia.io 11 points 4 days ago (3 children)
[–] Assman@sh.itjust.works 15 points 4 days ago

The black lines

[–] CodexArcanum@lemmy.world 7 points 4 days ago (1 children)

The semi-circle is one side, then the 2 straight edges, and the arc between them is the 4th side.

[–] Doll_Tow_Jet-ski@fedia.io 6 points 4 days ago (1 children)

That's what I thought. The only way on which this has four sides is if the semi -circle is a side. But if that's the case, then I don't know wha the definition of "side" is

[–] bstix@feddit.dk 7 points 4 days ago (1 children)

Knock knock. Do you have a moment to discuss non-euclidean geometry?

[–] Doll_Tow_Jet-ski@fedia.io 9 points 4 days ago

/slams door

[–] UrLogicFails@beehaw.org 5 points 4 days ago (1 children)

Someone may want to double-check my math on this one, but the length of the sides will be dependant on the radius of the smaller circle

ϴ=π+1-√(π^2+1), l=(2π-ϴ)r_1, l is the length of the sides. r_1 is the radius of the smaller circle

[–] m0darn@lemmy.ca 4 points 4 days ago* (last edited 4 days ago) (1 children)

I look at your diagram and see:

ϴ= L/(L+R)

And

2π-ϴ = L/R

I solved those (using substitution, then the quadratic formula) and got

L= π-1 ± √(1+π²) ~= 5.44 or -1.16

Whether or not a negative length is meaningful in this context is an exercise left to the reader

Giving (for L=5.44):

ϴ~= 0.845 ~~48.4° 

I'm surprised that it solved to a single number, maybe I made a mistake.

[–] UrLogicFails@beehaw.org 3 points 4 days ago

That lines up pretty similarly with what I found also. The angle should be a constant since there is only one angle where the relationship would be true. I just left it in terms of π because I try to avoid rounding.

Having said that, L would be a ratio of r; which I think lines up with what you found as well.

[–] affiliate@lemmy.world 8 points 4 days ago (1 children)

it’s homeomorphic to a square, so why not

[–] hydroptic@sopuli.xyz 2 points 4 days ago

See, you get it