Day 16: Reindeer Maze

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[-] mykl@lemmy.world 3 points 2 years ago* (last edited 2 years ago)

Uiua

Uiua's new builtin path operator makes this a breeze. Given a function that returns valid neighbours for a point and their relative costs, and another function to test whether you have reached a valid goal, it gives the minimal cost, and all relevant paths. We just need to keep track of the current direction as we work through the maze.

(edit: forgot the Try It Live! link)

Data  ← ≡°□°/$"_\n_" "#################\n#...#...#...#..E#\n#.#.#.#.#.#.#.#^#\n#.#.#.#...#...#^#\n#.#.#.#.###.#.#^#\n#>>v#.#.#.....#^#\n#^#v#.#.#.#####^#\n#^#v..#.#.#>>>>^#\n#^#v#####.#^###.#\n#^#v#..>>>>^#...#\n#^#v###^#####.###\n#^#v#>>^#.....#.#\n#^#v#^#####.###.#\n#^#v#^........#.#\n#^#v#^#########.#\n#S#>>^..........#\n#################"
D₄    ← [1_0 ¯1_0 0_1 0_¯1]
End   ← ⊢⊚=@EData
Costs ← :∩▽⟜:≡(≠@#⊡:Data⊢).≡⊟⊙⟜(+1×1000¬≡/×=)+⟜:D₄∩¤°⊟
path(Costs|≍End⊙◌°⊟)⊟:1_0⊢⊚=@SData
&p ⧻◴≡⊢/◇⊂ &p :

[-] Acters@lemmy.world 2 points 2 years ago

uiua is insane, such small code footprint to fit a maze solver like algo

this post was submitted on 16 Dec 2024

7 points (76.9% liked)

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