466
Peak code reuse (lemmy.nz)
submitted 11 months ago by orhtej2@eviltoast.org to c/programmer_humor@programming.dev
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[-] cogman@lemmy.world 7 points 11 months ago* (last edited 11 months ago)

Fixed

boolean isOdd(int num) {
  if(num == 1)
    return true;
  if(num > 0)
    return isEven(num - 1);
  else
    return isEven(num + 1);
}

boolean isEven(int num) {
  if(num > 0)
    return isOdd(num - 1);
  else
    return isOdd(num + 1);
}
[-] affiliate@lemmy.world 11 points 11 months ago

the downside with this approach is that it will eventually terminate. the version in the original post has the advantage of giving me plenty of time to contemplate life’s many mysteries.

[-] cogman@lemmy.world 4 points 11 months ago

What can I say, I'm a performance nerd.

[-] Rednax@lemmy.world 1 points 11 months ago

Why the complicated if statements to check the sign? Just let the number overflow. Would be functionaly the same, and result in much prettier code.

[-] cogman@lemmy.world 6 points 11 months ago

That's a platform dependent change. Overflow is undefined behavior. I'd rather have my code portable so it can run on my Univac 1101.

[-] Valmond@lemmy.world 1 points 11 months ago

isEeven(∞);

this post was submitted on 12 Sep 2025
466 points (98.7% liked)

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