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gender math [gay calculator]
(lemmy.nz)
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this post was submitted on 23 Sep 2026
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Wouldn't a unit vector make more sense, in this case, rather than binding any one dimesion to an arbitrary range?
Also, Im a bit confused on "n" both in its calculation and value as a dimension?
Also, cross products wouldn't give you a single value. You'd get the vector orthogonal to both.
This is a unit vector. They bound Masc and Fem to 0 to 1, sure, but what they meant about using NB to make sure it always adds up to 1 was attempting to set this up as a unit vector. It was just a little clumsily defined.
So then given that it's a unit vector, "n" is there to represent non-adherence to the Masc and Fem spectrum. Someone can't be half Masc in a unit vector without being half-something-else, and if that something else isn't Fem, then it's NB. Their expression would be some Masc but also some gender-non-specific things, without a lot of Fem traits.
That's what they're going for, at least.
the sum of the dimensions equalling to 1 doesn't make it a unit vector. For it to be a unit vector its magnitude must equal 1. There is just an overlap where some values, like
<1,0,0>or<0,1,0>that both sum to 1 and have a magnitude of 1. We expect that the domains of m,f,n are in 0-1.So a vector like
<0.5, 0, 0.5>sums to 1.... but it's not a unit vector, because its' magnitude ( sqrt( M^2^ + F^2^ + N^2^ )) is 0.7071... not a unit vector. To make it a unit you'd have to divide each of the dimensions by that magnitude. So the unit vector of<0.5, 0, 0.5>is<0.70711..., 0, 0.70711...>Calculating the unit vectors prior to doing the dot/cross products means you're doing operations on two equally sized vectors which would give more consistent results.
I don't really understand your first point.
n can be determined according to this equation:
f + n + m = 1, and all the values are bounded by[0; 1]additionally.The cross product gives you the orthogonal vector, this is why they take the absolute value of it.