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Measuring performance in a hardware-agnostic way
(lemmy.blahaj.zone)
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this post was submitted on 02 Dec 2023
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Sure, but that makes a lot of optimizations nonexistent (e.g. cloning the input on an O(n) algorithm is "free")
You don't need to use big-O. You can calculate the full complexity in algebraic notation. It's just a lot more work as you don't get to discard terms.