this post was submitted on 14 Jul 2024
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Edit: I didn't read the entirety of the problem, but in any case, this should help you state almost anything regarding the simple math. Note that in actuality, I don't think there would be a true meeting place due to orbital paths, but if you treat it as a linear "train" problem, this is how I would do it.
This may not be the simplest, but here's an easy way to just use lots of substitution and basic algebra.
Let t = time in days to meet
Let a = speed (not velocity) of rocket A
Let b = speed (not velocity) of rocket B
1 = 200 * a
1 = 150 * b
200a = 150b
a = (3/4)b
1 = (t * a) + (t - 30) * b
Substitute for a
1 = (3/4)bt + bt - 30b = (7/4)b - 30b
Recall that 1 = 150 * b and set these equal
150b = (7/4 * t - 30) b
Divide by b
150 = 1.75t - 30
1.75t = 180
t ~ 103 days
At 103 days, the ships will meet, and since it's over half the time it takes for rocket A to reach Earth, the meeting point will be closer to Earth.