67
THIS HOLE WAS MADE FOR ME
(lemmy.nz)
Real title:
Differentiation of Differentiation by Zundamon's Theorem
Wenn wir 5 als Operator definieren, der eine Funktion verfünffacht, dann ist das korrekt (wenn auch etwas cursed)
Das ist gar kein Problem, das ist 1
"d/dr... (d/dr... (d/dr(r)...)"
Well I learnt aboout a good channel today, so thanks for sharing. The premise was interesting, and the "presentation" was certianly something
So d/d(d/dx) is then just [-,d/dx]?
this post was submitted on 15 Jun 2025
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