2(4)^2=(2x4)^2=8^2=64
Yes, that's right. Brackets before Exponents, as per the order of operations rules.
You can’t distribute into a bracket
You know that's literally what The Distributive Law says you must do, right? Unless you have a source somewhere saying there's an exception?
Apparently you didn't bother reading any of the links I gave you, so here's one of the many textbooks which says you must distribute...

In case that's unclear, that means that 2x² and 2(x)² aren't the same thing (since 2(x)=(2x) by definition).
wolfram syntax
You know Wolfram disobeys The Distributive Law, right? I know I'm not the only one who knows this. Is that why you're insisting your way is right? Cos they're known to be wrong about this.
If you respond with more bullshiting,
You call quoting Maths textbooks "bullshiting"?


A Maths textbook.
It's standard in every Maths textbook.
The "few people" are Maths teachers and Maths textbook authors.
There's no such thing as implicit multiplication
No, what people are calling "implicit multiplication" is either The Distributive Law - which is the first step in solving Brackets - or Terms - and neither of these things is "multiplication". Multiplication literally refers to multiplication symbols only.
The division symbol is used - it is not the same thing as a fraction bar.
No, it's the same as x÷(y*z).
Terms, The Distributive Law, are why it's treated differently.